Level 6Exercise #132

Accept anything speakable

Define a structural Speaker protocol with speak(), then call it without requiring inheritance.

What you’ll practice

This Level 6 exercise focuses on Protocol in the Professional curriculum. Solve the challenge prompt above using clear, idiomatic Python and the relevant language or standard-library tools.

Relevant Python reference: typing — Support for type hints.

Sample Test Cases

Example #1

Input:announce(type('Speaker', (), {'speak': lambda self: 'ready'})())

Output:'ready'

Reference Solution

Reveal Reference Solution

def announce(speaker: 'Speaker') -> str:
    from typing import Protocol
    class Speaker(Protocol):
        def speak(self) -> str: ...
    return speaker.speak()

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Accept anything speakable

What you’ll practice

Sample Test Cases

Further Reading

Reference Solution